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Java常用字符串反转的五种方案大纲

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java程序中如何一个字符串进行反转?或者在字符串中指定部分进行反转的方法有哪些?为帮助大家解决这个疑问,yjbys小编为同学们分享最新Java常用字符串反转的五种方案,快来看看吧!

Java常用字符串反转的五种方案大纲

Java常用字符串反转的5种方案,代码如下:

  第一个类是运行类

package everse;

import ner;

public class Run {

public Run() {

t("请输入一个字符串:");

Scanner sc = new Scanner();

String str = ();

tln();

String reversedStrByArray = new Reverse(str)rseByArray();

tln("对应反转字符串为[Array]:"+ reversedStrByArray);

String reversedStrByStack = new Reverse(str)rseByStack();

tln("对应反转字符串为[Stack]:"+ reversedStrByStack);

String reversedStrBySort = new Reverse(str)rseBySort();

tln("对应反转字符串为[逆序遍历]:"+ reversedStrBySort);

String reversedStrByBit = new Reverse(str)rseByBit();

tln("对应反转字符串为[位运算]:"+ reversedStrByBit);

String reversedStrByRecursive = new Reverse(str)rseByRecursive(str);

tln("对应反转字符串为[递归]:"+ reversedStrByRecursive); }

public static void main(String[] args) {

new Run();

}

}

  第二段代码是实现类

package everse;

import k;

public class Reverse {

String str = new String();

public Reverse(String str) {

= str;

}

//用数组实现

public String reverseByArray() {

if(str == null th() == 0) {

return str;

}

int len = th();

char[] chArray = arArray();

for(int i= 0; i< len/2; i++) {

char temp;

temp = chArray[i];

chArray[i] = chArray[len- 1- i];

chArray[len- 1- i] = temp;

}

return new String(chArray);

}

//用栈实现

public String reverseByStack() {

if(str == null th() == 0) {

return str;

}

Stack strStack = new Stack();

char[] chArray = arArray();

for(Character ch: chArray) {

(ch);

}

int len = th();

for(int i= 0; i< len; i++) { chArray[i] = ();

}

return new String(chArray);

}

//用逆序遍历实现

public String reverseBySort() {

if(str == null th() == 0) {

return str;

}

StringBuilder sb = new StringBuilder();

for(int i= th()- 1; i>= 0; i--) {

nd(At(i));

}

return ring();

}

//用位运算实现

public String reverseByBit() {

if(str == null th() == 0) {

return str;

}

char[] chArray = arArray();

int len = th();

for(int i= 0; i< len/ 2; i++) {

chArray[i]^= chArray[len- 1- i];

chArray[len- 1- i]^= chArray[i];

chArray[i]^= chArray[len- 1- i];

}

return new String(chArray);

}

//用递归实现

public String reverseByRecursive(String str) {

if(str == null th() == 0) {

return str;

}

int len = th();

if(len == 1) {

return str;

} else {

return reverseByRecursive(tring(1))+ At(0);

}

}

}